SOLUTION: There is tank that holds 400 gallons of water. You'

SOLUTION: There is tank that holds 400 gallons of water. You've got one pipe that can fill it up in 15 minutes. Another pipe can empty it in 40 minutes. If both pipes are open at the same ti Algebra -> Rate-of-work-word-problems -> SOLUTION: There is tank that holds 400 gallons of water. You've got one pipe that can fill it up in 15 minutes. Another pipe can empty it in 40 minutes. If both pipes are open at the same ti Log On

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A tank that hold 400 gallon of water can be Question 322437: There is tank that holds 400 gallons of water. You've got one pipe that can fill it up in 15 minutes. Another pipe c filed by one pipe in 15 minutes and an empty it in 40 minutes. If both pipes are open at the same time, how long does it take to fill the tank? emptied... (answered by Found 2 solutions by ptaylor, Edwin McCravy: josgarithmetic,josmiceli,ikleyn) One pipe can fill a tank in 45 minutes and another pipe can fill it in 30 minutes. if... (answered by ramkikk66) Answer by ptaylor(2194) (Show Source): You can put this solution on YOUR website! Let t = time it takes to fill the tank when both pipes are open One pipe fills at the rate of 1/15 tank (or 400/15 = 26 2/3 gal) per min The other pipe empties at the rate of 1/40 tank (or 400/40=10 gal) per min Together they fill at the rate of 1/15 - 1/40= 8/120 - 3/120=5/120 tank (or (5/120)*400=16 2/3 gal per min So our equation to solve is: (16 2/3)*t=400 or (50/3)t=400 50t=1200 t=24 min CK In 24 min one pipe fills 26 2/3 * 24 or (80/3)*24=640 gal In 24 min other tank empties 10*24 or 240 gal 640-240=400 400=400 Hope this helps---ptaylor

Answer by Edwin McCravy(16661) (Show Source): You can put this solution on YOUR website! There is tank that holds 400 gallons of water. You've got one pipe that can fill it up in 15 minutes. Another pipe can empty it in 40 minutes. If both pipes are open at the same time, how long does it take to fill the tank? Make this chart: No. of tanks Time in Rate in filled minutes tanks/minute fill pipe drain pipe both together Let x = the number of minutes to fill the tank when both are open. Fill x in for the time for "both together". Also fill in the given times for the two pipes indivisuallty, 15 and 40 minutes:

No. of tanks Time in Rate in filled minutes tanks/minute fill pipe 15 drain pipe 40 both together x Next fill in the number of tanks filled. The drain pipe "fills" "negative one" tanks. (To drain one tank is considered the same mathematically as "filling negative one tanks"). So we fill in for the number of tabks "filled": No. of tanks Time in Rate in filled minutes tanks/minute fill pipe +1 15 drain pipe -1 40 both together +1 x Next we fill in the rates by dividing tanks by minutes:

No. of tanks Time in Rate in filled minutes tanks/minute fill pipe +1 15 +1/15 drain pipe -1 40 -1/40 both together +1 x +1/x Make the equation from Rate of fill pipe + Rate of drain pipe = Reate of both together

Multiply through by LCM of 120x: Answer: 24 minutes Edwin

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