Quadratic Equations Class 10 | Full Chapter Solutions NCERT Solutions for Class 10 Maths Chapter 4: Quadratic Equations provide answers to all the problems in the Class 10 Maths NCERT textbook, aiding students in their CBSE exam preparations. Join Major Kalshi Classes for expertly solved problems by subject specialists. These solutions offer detailed, step-by-step guidance for each question. It's crucial to approach the exercises in this chapter diligently to achieve good scores in exams, as Maths requires both comprehension and practice. This resource offers tips and tricks for solving problems easily. A quadratic equation in the variable x follows the form ax^2 + bx + c = 0, where a, b, and c are real numbers, and a ≠ 0, known as the standard form of a quadratic equation. NCERT Solutions for Class 10 Maths Chapter 4 PDF With step-by-step explanations and detailed solutions, students can enhance their understanding and proficiency in solving quadratic equations. NCERT Solutions for Class 10 Maths Chapter 4 PDF
NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations NCERT Solutions for Class 10 Chapter 4 Quadratic Equations provide comprehensive solutions to the problems presented in the NCERT textbook. These solutions, created by our subject experts, provide step-by-step explanations to help students understand the concepts thoroughly. With detailed solutions and clear explanations, students can practice solving quadratic equations easily. By utilising these NCERT Solutions, students can strengthen their grasp of quadratic equations and improve their problem-solving skills.
NCERT Maths Chapter 4 Exercise 4.1 Solutions 1. Check whether the following are quadratic equations? (i) (x+1) 2 = 2(x-3) (ii) x 2 -2x = (-2)(3-x) (iii) (x − 2) (x + 1) = (x − 1) (x + 3) (iv) (x − 3) (2x + 1) = x (x + 5) (v) (2x − 1) (x − 3) = (x + 5) (x − 1) (vi) x 2 +3x+1 = (x-2) 2 (vii) (x+2) 3 = 2x(x 2 -1) (viii) x 3 -4x 2 -x+1 = (x-2) 3 Answer: An equation of the form ax 2 +bx+c = 0, a ≠ 0 and a, b, and c are real numbers, is called a quadratic equation. (i) (x+1) 2 = 2(x-3) x 2 +2x+1 = 2x-6 x 2 +2x+1 -2x+6 = 0 x 2 +7 = 0 Comparing above equation with ax 2 +bx+c = 0, we have a = 1≠ 0, b = 0, c = 7 Hence the given equation is quadratic equation. (ii) x 2 -2x = (-2)(3-x) x 2 -2x = -6+2x x 2 -2x -2x+6 = 0 x 2 -4x+6 = 0 Comparing above equation with ax 2 +bx+c = 0, we have a = 1≠ 0, b = -4, c = 6 Hence the given equation is quadratic equation.
(iii) (x-2)(x+1) = (x-1)(x+3) x 2 -2x+x-2 = x 2 -x+3x-3 x 2 -2x+x-2 -x 2 +x-3x+3= 0 -3x+1 = 0 Comparing above equation with ax 2 +bx+c = 0, we have a = 0, b = -3, c = 1 Hence the given equation is not quadratic equation.
(iv) (x-3)(2x+1) = x(x+5) x 2 -6x+x-3 = x 2 +5x x 2 -6x+x-3 -x 2 -5x = 0 -10x-3 = 0 Comparing above equation with ax 2 +bx+c = 0, we have a = 0, b = -10, c = -3 Hence the given equation is not quadratic equation.
(v) (2x-1)(x-3) = (x+5)(x-1) 2x 2 -6x-x+3 = x 2 +5x-x-5 2x 2 -6x-x+3 -x 2 -5x+x+5 = 0 x 2 -11x+8 = 0 Comparing above equation with ax 2 +bx+c = 0, we have a = 1 ≠ 0, b = -11, c = 8 Hence the given equation is quadratic equation.
(vi) x 2 +3x+1 = (x-2) 2 x 2 +3x+1 = x 2 -4x+4 x 2 +3x+1 -x 2 +4x-4= 0 7x-3 = 0 Comparing above equation with ax 2 +bx+c = 0, we have a = 0, b = 7, c = -3 Hence the given equation is not quadratic equation.
(vii) (x+2) 3 = 2x(x 2 -1) x 3 +6x 2 +12x+8 = 2x 3 -2x x 3 +6x 2 +12x+8 -2x 3 +2x = 0 x 3 – 6x 2 -14x-8 = 0 It is not in the form of ax 2 +bx+c = 0s Hence the given equation is not a quadratic equation. (viii) x 3 -4x 2 -x+1 = (x-2)3. x 3 -4x 2 -x+1 = x 3 -6x 2 +12x-8 x 3 -4x 2 -x+1 -x 3 +6x 2 -12x+8= 0 2x 2 -13x+9 = 0 Comparing above equation with ax 2 +bx+c = 0, we have a = 2 ≠ 0, b = -13, c = 9 Hence the given equation is quadratic equation. 2. (i) The area of the rectangular plot is 528 m 2. The length of the plot (in meters) is one more than twice its breadth. We need to find the length and breadth of the plot. Answer:
Let the breadth of the plot is x meters. Then, the length is (2x + 1) meters. Area = length × breadth 528 = x × (2x + 1) 528 = 2x 2 + x 2x 2 + x – 528 = 0 (ii) The product of two consecutive positive integers is 306. We need to find the integers. Answer: Let x and x+1 be two consecutive integers. Then, x(x + 1) = 306 x 2 + x – 306 = 0 (iii) Rohan's mother is 26 years older than him. The products of their ages (in years) 3 years from now will be 360. We would like to find Rohan's present age. Answer: Let x be the Rohan’s present age. Then, his mother’s present age is x+26 After 3 years theirs ages will be x+3 and x+26+3 = x+29 respectively. Hence, (x+3)(x+29) = 360 x 2 +3x+29x+87 = 360 x 2 +32x- 273 = 0 (iv) A train travels a distance of 480 km at a uniform speed. If the speed had been 8 km/h less, then it would have taken 3 hours more to cover the same distance. We need to find the speed of the train. Answer: Let speed of train be x km/h Time taken by train to cover 480 km = 480xhours If, speed had been 8km/h less then time taken would be (480x−8) hours According to given condition, if speed had been 8km/h less then time taken is 3 hours less. Therefore, 480x – 8 = 480x + 3 ⇒480 (1x – 8 − 1x) = 3 ⇒480 (x – x + 8) (x) (x − 8) = 3 ⇒480 × 8 = 3 (x) (x − 8).
This is a Quadratic Equation.
Download the MKC Learning App Get access to Class 10 Maths NCERT Solutions, mock tests, formula sheets, and video lectures by subject experts all in one place! Download Now and boost your CBSE preparation!
Watch Full Chapter Explanation on YouTube Confused about Quadratic Equations? Watch our step-by-step video explanation of Chapter 4 – Quadratic Equations on the Major Kalshi Classes YouTube Channel. Watch Now: [MKC YT Chapter Video] Subscribe now and never miss a topic!
