The soot produced by a garbage incinerator spreads out in a circular pattern. The depth, H (r), in millimeters, of the soot deposited each month at a distance r kilometers from the incinerator is given by H(r) = 0.118e^(-2.4 r). Write a
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definite integral (with independent variable r) giving the total volume of soot... show more Update: sertbl: First of all, the problem needs a number. 2*pi*r * int(0,5){H(r)} doesn't give me a number, since the r in
2*pi*r is not constant. Second, for the first part, I can only fill out the integrand, so everything must be in the int(0,5)
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Best Answer: you just need to use H(r). the h is the depth/month, so integrating gives you the depth. well, that
doesnt completely solve it. that gives you the total cut-away area.
Calculus II Volume of Revolution Help!!? Help with Calculus II Volume Question?
the 2pi*r comes in after the integral. so you get v=2*pi*r*integral(0,5){H(r)}
Calculus II Problem: Volume? sertrbl · 9 years ago 0
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Calculus II volume question? Calculus II - Volume of Solid?
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Answer Questions Please help with these three Calculus problems.?
Use a double necessary. the 1st necessary calculates the area below the curve. the 2nd necessary calculates the area you calculated in the previous over a span of 360degrees (a rotation). so it would be: necessary(0,2pi)
Use a graphing utility to complete the table and estimate the limit as x approaches infinity.?
necessary (0,3) y dx dtheta, the place y is the equation you have above.
A math problem. need help?
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