The number of gallons of wat.cr in a tank t minutes after the tank has ...

The number of gallons of wat.cr in a tank t minutes after the tank has ...

Math Science More Log in Search Slader The number of gallons of wat.cr in a tank t minutes after the tank has started to drain is /Q(t) = 200(30 ...

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Oct 29, 2009 - Find the slope when t = 0 and t = 10. y2-y1 / x2-x1 (180000 - 80000) / (10 - 0) = 10000 gallons / minute.

Mar 3, 2012 - find the derivative. Q'(t)=-400(30-t)=-12000+400t now plug in 10. Q'(10)=-12000+400(10)=-12000+4000=-800... So the water is running out at -8000 gallons per minute. to find how much water is left in the tank. Q(10)=200(30-10)^2=300(400)

The number of gallons of water in a tank t minutes after the tank has started to drain is Q(t) = 200(30 − t)2. 1. (a) What is the average rate at which the water flows out during the first ten minutes? (b) during the five minutes from t = 5 to t =

Aug 8, 2009 - Your suspicion is correct. Q'(t) = 200 * 2 * (-1) * (30 - t).....The (-1) is from the chain rule -> it is the derivative of 30 - t. So Q'(t) = -400 * 20 = - 8,000 gallons per minute. Notice that this answer is negative because the quant

Answer to The number of gallons of water in a tank t minutes after the tank has started to drain is Q (t) = 400 - t^2. (a) Do you ...

The number of gallons of water in a tank t minutes after the tank has started to drain is Q(t)=200(30-t)^2. a) How fast is the water running out of the tank at the end of 10 minutes? b) What is the average rate at which the water flows out of the tan

Answer to Draining a tank The number of gallons of water in a tank t minutes after the tank has started to drain is Q(t) = 200(30....

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