Loading...

Science

More

Log in

Search Slader

The number of gallons of wat.cr in a tank t minutes after the tank has started to drain is /Q(t) = 200(30 - t) 2• How fast is the water running out at the end of 10 min? What is the average rate at which the water flows out during the first 10 min? report this ad

3.0

BLACKSTAR 1

We have to find the derivative of this to find rate of change.

2

Factor it out to use only power rule.

3

4

Q'(t)= -12000+400t

Used power rule, this is derivative/rate of change of the tank flowing.

-12000+400(10)=-8000 gallons/min

Plug in t as 10, and get -8000 gallons/min. This is the answer to the first question.

report this ad

5

6

Plug it in and solve.

7

-10000 gal/min

Average is units gal/min, and -1000 is obtained from equation above.

RE S ULT

-8000 gal/min, -10000 gal/min

Submit

Add your comment reply

john

0

It's (30-t)^2 instead of (30-t^2)

show all comments

Search Title, Author, or ISBN

Slader has all your textbook answers!!!

2.0

T Y N A N A L E X… 1

Find the first derivative of Q(t) and plug t=10 to get the water's draining speed at 10 seconds. To find the average velocity over the first 10 minutes, take the change in water divided by the change in time over that period.

RE S ULT

Instantaneous = -8000 gallons/minute, Average = -10000 gallons/minute

Submit

Add your comment reply

aznboy

0

When you used the power rule to take the derivative of Q(t), how does it become negative 400?

show all comments

report this ad

Slader

HOMEWORK SOLVED

About Advertise with us Alternative FAQs Legal

Copyright © 2018 Slader Made in NYC

Math
Science
More
Log in
Search Slader
The number of gallons of wat.cr in a tank t minutes after the tank has started to drain is /Q(t) = 200(30 ...

No documents